.49-2.8x+4x^2=16x^2+3.2x+1.6

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Solution for .49-2.8x+4x^2=16x^2+3.2x+1.6 equation: 



.49-2.8x+4x^2=16x^2+3.2x+1.6

We move all terms to the left:

.49-2.8x+4x^2-(16x^2+3.2x+1.6)=0

We add all the numbers together, and all the variables

4x^2-2.8x-(16x^2+3.2x+1.6)+0.49=0

We get rid of parentheses

4x^2-16x^2-2.8x-3.2x-1.6+0.49=0

We add all the numbers together, and all the variables

-12x^2-6x-1.11=0

a = -12; b = -6; c = -1.11;
Δ = b2-4ac
Δ = -62-4·(-12)·(-1.11)
Δ = -17.28
Delta is less than zero, so there is no solution for the equation

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